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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## If n!/(n-2)!<100, what is the greatest possible value of tagged by: Max@Math Revolution ##### This topic has 2 expert replies and 0 member replies ### GMAT/MBA Expert ## If n!/(n-2)!<100, what is the greatest possible value of [GMAT math practice question] If n!/(n-2)!<100, what is the greatest possible value of n? A. 8 B. 9 C. 10 D. 11 E. 12 _________________ Math Revolution Finish GMAT Quant Section with 10 minutes to spare. The one-and-only Worldâ€™s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. Only$99 for 3 month Online Course
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### GMAT/MBA Expert

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Max@Math Revolution wrote:
[GMAT math practice question]

If n!/(n-2)!<100, what is the greatest possible value of n?

A. 8
B. 9
C. 10
D. 11
E. 12
n!/(n-2)! < 100
(n*(n-1)*(n-2)!)/(n-2)! < 100
n*(n-1) <100

E) n of 12 doesn't hold as 121 >= 100
D) n of 11 doesn't hold as 110 >= 100
C) n of 10 does hold as 90 < 100
No need to test B and A

### GMAT/MBA Expert

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=>

We must have
n! / (n-2)! = n(n-1) < 100.
If n = 10, n(n-1) = 10*9 = 90 < 100.
If n = 11, n(n-1) = 11*10 = 110 > 100.

10 is the greatest value of n for which n!/(n-2)! < 100.

_________________

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