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If n is an integer greater than 6, which of the following

Expert replies
by BTGmoderatorDC » Wed May 22, 2019 3:48 am
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If n is an integer greater than 6, which of the following must be divisible by 3 ?

(A) n(n + 1)(n – 4)
(B) n(n + 2)(n – 1)
(C) n(n + 3)(n – 5)
(D) n(n + 4)(n – 2)
(E) n(n + 5)(n – 6)

OA A

Source: Official Guide
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Source: — Problem Solving |

by Brent@GMATPrepNow » Wed May 22, 2019 5:25 am
BTGmoderatorDC wrote:If n is an integer greater than 6, which of the following must be divisible by 3 ?

(A) n(n + 1)(n – 4)
(B) n(n + 2)(n – 1)
(C) n(n + 3)(n – 5)
(D) n(n + 4)(n – 2)
(E) n(n + 5)(n – 6)
One approach is to test values

If n = 7, we get:
(A) 7(7 + 1)(7 – 4) = (7)(8)(3). Definitely divisible by 3. KEEP
(B) 7(7 + 2)(7 – 1) = (7)(9)(6). Definitely divisible by 3. KEEP
(C) 7(7 + 3)(7 – 5) = (7)(10)(4). NOT divisible by 3. ELIMINATE.
(D) 7(7 + 4)(7 – 2) = (7)(11)(5). NOT divisible by 3. ELIMINATE.
(E) 7(7 + 5)(7 – 6) = (7)(12)(1). Definitely divisible by 3. KEEP

We're left with A, B, and E

Try n = 8. We get:
(A) 8(8 + 1)(8 – 4) = (8)(9)(4). Definitely divisible by 3. KEEP
(B) 8(8 + 2)(8 – 1) = (8)(10)(7). NOT divisible by 3. ELIMINATE.
(E) 8(8 + 5)(8 – 6) = (8)(13)(2). NOT divisible by 3. ELIMINATE.


Answer: A

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by Ian Stewart » Wed May 22, 2019 7:55 am
Among any three consecutive integers, you always have exactly one multiple of 3. So if one of our answers here was something like (n-1)(n)(n+1), the product of three consecutive integers, it would certainly be divisible by 3. We don't have something quite that easy, but if you look at answer A:

(n-4)(n)(n+1)

notice that n-4 and n-1 are exactly three apart, so if n-4 is divisible by 3, so is n-1. So (n-4)(n)(n+1) is divisible by 3 exactly when (n-1)(n)(n+1) is, and since (n-1)(n)(n+1) always is, A is the right answer.

But I think most people solve this question by testing numbers, which is a viable approach here.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

ianstewartgmat.com
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by Scott@TargetTestPrep » Mon May 27, 2019 4:20 am
BTGmoderatorDC wrote:If n is an integer greater than 6, which of the following must be divisible by 3 ?

(A) n(n + 1)(n – 4)
(B) n(n + 2)(n – 1)
(C) n(n + 3)(n – 5)
(D) n(n + 4)(n – 2)
(E) n(n + 5)(n – 6)

OA A

Source: Official Guide
We can let n = 7 and then analyze each answer choice:

A) 7(8)(3) is divisible by 3.

B) 7(9)(6) is divisible by 3.

C) 7(10)(2) is not divisible by 3.

D) 7(11)(5) is not divisible by 3.

E) 7(12)(1) is divisible by 3.

We can eliminate choices C and D.

Now let n = 8 and analyze the remaining 3 choices:

A) 8(9)(4) is divisible by 3.

B) 8(10)(7) is not divisible by 3.

E) 8(13)(2) is not divisible by 3.

We see that the correct choice must be A.

Alternate Solution:

Let’s analyze each answer choice:

A) If n is divisible by 3, then the product n(n + 1)(n - 4) is also divisible by 3. If n produces a remainder of 1 when divided by 3 (for example, n = 7), then n - 4 must be divisible by 3. Finally, if n produces a remainder of 2 when divided by 3, n + 1 is divisible by 3. In either case, we see that the product has a factor that is a multiple of 3; therefore the product is always divisible by 3.

Answer: A

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