Hi Mo2men,
We're told that N is a positive integer. We're asked for the number of different factors N has. This question can be solved with a mix of TESTing VALUES and Number Property rules.
1) N/5 is a prime number.
IF....
N = 10, the factors are 1, 2, 5 and 10 and the answer to the question is 4
N = 15, the factors are 1, 3, 5 and 15 and the answer to the question is 4
N = 25, the factors are 1, 5 and 25 and the answer to the question is 3
Fact 1 is INSUFFICIENT
2) N has only two different prime factors.
IF....
N = 10, the factors are 1, 2, 5 and 10 and the answer to the question is 4
N = 20, the factors are 1, 2, 4, 5, 10 and 20 and the answer to the question is 6
Fact 2 is INSUFFICIENT
Combined, we know...
N/5 is a PRIME
N has ONLY 2 different prime factors
Since N/5 is prime, one of the two prime factors MUST be a 5 (to 'cancel out' the 5 in the denominator). Whatever the 'other' prime is, it can only show up ONCE in the prime factorization of N. If it showed up more than once, then N/5 would NOT be prime.
For example, 45 = (3)(3)(5), but 45/5 = 9 - which is NOT prime (so N CANNOT be 45).
In addition, the 5 can show up JUST ONCE. If it showed up more than once, then N/5 would NOT be prime.
For example, 75 = (3)(5)(5), but 75/5 = 15 - which is NOT prime (so N CANNOT be 75).
Thus, the 2 different prime factors are the ONLY factors of N that are not 1 or N. Under these conditions, there will ALWAYS be 4 factors:
1
(first prime)
(second prime)
N ... (the product of the two primes).
Combined, SUFFICIENT
Final Answer: C
GMAT assassins aren't born, they're made,
Rich