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If \(N = \dfrac13 + \dfrac1{3^2} +\dfrac1{3^3},\) then \(N\) is between

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by M7MBA » Sun Jun 27, 2021 12:59 am
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If \(N = \dfrac13 + \dfrac1{3^2} +\dfrac1{3^3},\) then \(N\) is between

A. \(0\) and \(\dfrac19\)

B. \(\dfrac19\) and \(\dfrac13\)

C. \(\dfrac13\) and \(\dfrac89\)

D. \(\dfrac89\) and \(\dfrac43\)

E. \(\dfrac43\) and \(2\)

Answer: C

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Re: If \(N = \dfrac13 + \dfrac1{3^2} +\dfrac1{3^3},\) then \(N\) is between

by Brent@GMATPrepNow » Mon Jun 28, 2021 6:13 am
M7MBA wrote: ↑
Sun Jun 27, 2021 12:59 am
 If \(N = \dfrac13 + \dfrac1{3^2} +\dfrac1{3^3},\) then \(N\) is between

A. \(0\) and \(\dfrac19\)

B. \(\dfrac19\) and \(\dfrac13\)

C. \(\dfrac13\) and \(\dfrac89\)

D. \(\dfrac89\) and \(\dfrac43\)

E. \(\dfrac43\) and \(2\)

Answer: C

Source: GMAT Prep

N = 1/3 + 1/3^2 +1/3^3
= 1/3 + 1/9 + 1/27
= 9/27 + 3/27 + 1/27
= 13/27

C) between 1/3 and 8/9 is the same as between 9/27 and 24/27
Since 13/27 is between 9/27 and 24/27, the correct answer is C
Brent Hanneson - Creator of GMATPrepNow.com
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