Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

if n=4p, where..!

Expert replies
Source: — Problem Solving |

by [email protected] » Sun Jul 06, 2014 7:14 am
HI chaitanya.bhansali,

This question can be solved rather easily by TESTing VALUES:

We're told that N = 4P and that P is a prime number greater than 2. Let's TEST P = 3; so N = 12

The question now asks how many DIFFERENT positive EVEN divisors does 12 have, including 12?

12:
1,12
2,6
3,4

How many of these divisors are EVEN? 2, 4, 6, 12 …..4 even divisors.

Final Answer: C

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion

by GMATinsight » Sun Jul 06, 2014 7:36 am
Hi Chaitanya,

The number of factors can also be calculated this way

Total calculated factors should be combination of (powers of 2 and powers of P with minimum power of 2 as 1 since every factor must be an even number)

2^1 P^0
2^2 P^1
____________________
2 values x 2 values = [spoiler]4 Factors Option-C[/spoiler]
"GMATinsight"Bhoopendra Singh & Sushma Jha
Most Comprehensive and Affordable Video Course 2000+ CONCEPT Videos and Video Solutions
Whatsapp/Mobile: +91-9999687183 l [email protected]
Contact for One-on-One FREE ONLINE DEMO Class Call/e-mail
Most Efficient and affordable One-On-One Private tutoring fee - US$40-50 per hour
Join the discussion

by GMATinsight » Sun Jul 06, 2014 7:38 am
The above method is based on the following method


Image
"GMATinsight"Bhoopendra Singh & Sushma Jha
Most Comprehensive and Affordable Video Course 2000+ CONCEPT Videos and Video Solutions
Whatsapp/Mobile: +91-9999687183 l [email protected]
Contact for One-on-One FREE ONLINE DEMO Class Call/e-mail
Most Efficient and affordable One-On-One Private tutoring fee - US$40-50 per hour
Join the discussion

by GMATinsight » Sun Jul 06, 2014 7:46 am
For more information on number of factors calculation of any number, please refer to the below mentioned links.

https://www.cut-the-knot.org/blue/NumberOfFactors.shtml

https://www.wikihow.com/Find-How-Many-Fa ... n-a-Number
"GMATinsight"Bhoopendra Singh & Sushma Jha
Most Comprehensive and Affordable Video Course 2000+ CONCEPT Videos and Video Solutions
Whatsapp/Mobile: +91-9999687183 l [email protected]
Contact for One-on-One FREE ONLINE DEMO Class Call/e-mail
Most Efficient and affordable One-On-One Private tutoring fee - US$40-50 per hour
Join the discussion

by Matt@VeritasPrep » Sun Jul 06, 2014 5:50 pm
chaitanya.bhansali wrote:if n=4p, where p is a prime number greater than 2, how many DIFFERENT positive EVEN divisors does n have, including n?

A) 2
B) 3
C) 4
D) 6
E) 8
Probably the easiest way is to list them:

* 2
* 4
* 2p
* 4p

And you're done!
Join the discussion

by Jeff@TargetTestPrep » Tue Jul 28, 2015 2:06 pm
chaitanya.bhansali wrote:if n=4p, where p is a prime number greater than 2, how many DIFFERENT positive EVEN divisors does n have, including n?

A) 2
B) 3
C) 4
D) 6
E) 8
Solution:

This is an interesting question because we are immediately given the option to insert any prime number we wish for p, as long as it’s greater than 2. Since this is a problem-solving question, and there can only be one correct answer, we can select any value for p, as long as it is a prime number greater than 2. We want to work with small numbers if possible, so we can select 3 for p. Thus, we have:

n = 4 x 3

n = 12

Next we have to determine all the factors, or divisors, of p. Remember, the term “factor” is synonymous with the term “divisor.”

1, 12, 6, 2, 4, 3

From this we see that we have 4 even divisors: 12, 6, 2, and 4.

If you are concerned that trying just one value of p might not substantiate the answer, try another value for p. Let’s say p = 5, so

n = 4 x 5

n = 20

The divisors of 20 are: 1, 20, 2, 10, 4, 5. Of these, 4 are even: 20, 2, 10 and 4. As we can see, again we have 4 even divisors.

In fact, no matter what the value of p is, as long as it is a prime number greater than 2, n will always have 4 even divisors.

The answer is C

Jeffrey Miller
Head of GMAT Instruction
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews
Join the discussion

by nikhilgmat31 » Tue Jul 28, 2015 11:53 pm
Answer is C

all the prime number grtr than 2 are odd.

4 * odd number is even number which is multiple of 2,4,2n,4n so it will always be 4.
Join the discussion