BTGmoderatorDC wrote:Five friends play blackjack in Las Vegas and lose an average of $100 each. If the losses of two of the friends total $380, what is the average loss of the other friends?
A. $40
B. $60
C. $100
D. $120
E. $1,900
Let A, B, C, D and E represent the LOSSES (in dollars) of the 5 friends
Five friends play blackjack in Las Vegas and lose an average of $100 each.
So, we can write: (A+B+C+D+E)/5 = 100
Multiply both sides by 5 to get:
A+B+C+D+E = 500
If the losses of two of the friends total $380, what is the average loss of the other friends?
We can write:
A+B = 380
Take:
A+B+C+D+E = 500 and replace
A+B with
380
We get:
380 +
(C+D+E) = 500
Subtract 380 from both sides to get: C+D+E =
120
So, the AVERAGE loss of C, D and E (the other friends) = (C+D+E)/3 =
120/3 = 40
Answer: A
Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
