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Five friends play blackjack in Las Vegas and lose an average

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Five friends play blackjack in Las Vegas and lose an average

by BTGmoderatorDC » Sun Jul 14, 2019 7:48 pm

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Five friends play blackjack in Las Vegas and lose an average of $100 each. If the losses of two of the friends total $380, what is the average loss of the other friends?

A. $40
B. $60
C. $100
D. $120
E. $1,900

OA A

Source: Princeton Review
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by Brent@GMATPrepNow » Mon Jul 15, 2019 6:36 am
BTGmoderatorDC wrote:Five friends play blackjack in Las Vegas and lose an average of $100 each. If the losses of two of the friends total $380, what is the average loss of the other friends?

A. $40
B. $60
C. $100
D. $120
E. $1,900
Let A, B, C, D and E represent the LOSSES (in dollars) of the 5 friends

Five friends play blackjack in Las Vegas and lose an average of $100 each.
So, we can write: (A+B+C+D+E)/5 = 100
Multiply both sides by 5 to get: A+B+C+D+E = 500

If the losses of two of the friends total $380, what is the average loss of the other friends?
We can write: A+B = 380

Take: A+B+C+D+E = 500 and replace A+B with 380
We get: 380 + (C+D+E) = 500
Subtract 380 from both sides to get: C+D+E = 120

So, the AVERAGE loss of C, D and E (the other friends) = (C+D+E)/3 = 120/3 = 40

Answer: A

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by swerve » Mon Jul 15, 2019 9:57 am
average loss: \(100= 380+\frac{3x}{5}\)
solve for \(x\) we get: \(x=40\)

So the average loss of other friends: \(\frac{120}{3}= 40\$\Rightarrow\) option __A__
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by Scott@TargetTestPrep » Fri Jul 26, 2019 11:08 am
BTGmoderatorDC wrote:Five friends play blackjack in Las Vegas and lose an average of $100 each. If the losses of two of the friends total $380, what is the average loss of the other friends?

A. $40
B. $60
C. $100
D. $120
E. $1,900

OA A

Source: Princeton Review
The total loss of all the friends is 500 dollars. Since two friends lost 380 dollars, the remaining 3 friends lost a total of 500 - 380 = 120 dollars, or an average of 120/3 = 40 dollars.

Answer: A

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