AAPL Moderator View User Profile Posts: 2599 Joined: Sun Oct 29, 2017 2:08 pm Followed by:2 members If \(k\) is a positive integer, what is the maximum value of \(k\) such that \(\dfrac{65!}{6^k}\) is an integer? by AAPL » Wed Oct 04, 2023 7:39 am Timer 00:00 Your Answer A B C D E Global Stats If \(k\) is a positive integer, what is the maximum value of \(k\) such that \(\dfrac{65!}{6^k}\) is an integer? A. \(21\) B. \(28\) C. \(30\) D. \(36\) E. \(63\) OA C Top Quote
