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if each term in the sum a1 + a2 + ... is either 7 or 77

Expert replies

by Brent@GMATPrepNow » Mon Apr 20, 2015 5:59 am
Sweeeeeeeeeeeeeeeeeeet solution, Matt!
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by Jeff@TargetTestPrep » Sun Apr 26, 2015 6:29 am
lunarpower wrote:courtesy of user 'karenmeow'

if each term in sum a1+a2+...+an is either 7 or 77, and the sum equals 350, which can be n?

choices: 38, 39, 40, 41, 42
Solution:

We can let x be the number of terms that are 7 and y be the number of terms that are 77. Notice that x + y = n, the total number of terms. We can also set up the following equation

7x + 77y = 350

Dividing both sides by 7 we have:

x + 11y = 50

11y = 50 - x

y = (50 - x)/11

Because y is an integer, we know that (50 - x) must be a multiple of 11.

Thus, to make that true, variable x can only be 6, 17, 28 or 39.

If x = 6, y = 4, so n = 10.

If x = 17, y = 3, so n = 20.

If x = 28, y = 2, so n = 30.

If x = 39, y = 1, so n = 40.

We see that answer choice C is the only one that matches our possibilities for n.

Note: In looking at the equation x + 11y = 50, we also could have taken a units digit approach. We know that the units digit of x + 11y is a zero. We also know that 11 times any number will result in the same units digit as the original number. As an example let's take the number 2. 2 has a units digit of 2 and 2 x 11 = 22 also has a units digit of 2.

Thus, we can say that x + 11y will result in the same units digit as x + y. Since we know that x + 11y = 50, we know that x + 11y has a units digit of zero. This means that x + y (or "n" in this case) also has a units digit of zero. Since 40 is the only answer choice with a units digit of zero we know that is the correct answer.

The answer is C

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by akshaydhande » Mon Aug 22, 2016 8:30 am
I would suggest u directly take options and start to check

lets start with
38*7=266+77 near 350 but does not end in 0, next 77 will be too much
39*7=273+77 ==350 bingo 39 times 7 and 1 time 77 that is total 39+1=40 terms.
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by Matt@VeritasPrep » Thu Sep 01, 2016 6:18 pm
akshaydhande wrote:I would suggest u directly take options and start to check

lets start with
38*7=266+77 near 350 but does not end in 0, next 77 will be too much
39*7=273+77 ==350 bingo 39 times 7 and 1 time 77 that is total 39+1=40 terms.
That works too! Since the answers are so clustered around 40, I'd start there: 40 * 7 is 280, and if we drop one 7, we've got 39*7 + 77, or ... 350! What luck.
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