BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

For how many integers \(n\) is \(n + n = n\cdot n ?\)

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

Re: For how many integers \(n\) is \(n + n = n\cdot n ?\)

by Brent@GMATPrepNow » Mon May 11, 2020 9:40 am
Vincen wrote: ↑
Mon May 11, 2020 3:28 am
 For how many integers \(n\) is \(n + n = n\cdot n ?\)

a) None
b) One
c) Two
d) Three
e) More than three.

[spoiler]OA=C[/spoiler]

Source: Veritas Prep
Given: n + n = (n)(n)
Simplify both sides: 2n = n²
Subtract 2n from both sides to get: 0 = n² - 2n
In other words: n² - 2n = 0
Factor to get: n(n - 2) = 0
So, either n = 0 or n = 2
There are two solutions

Answer: C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Top

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 8086
Joined: Sat Apr 25, 2015 10:56 am
Location: Los Angeles, CA
Thanked: 43 times
Followed by:29 members

Re: For how many integers \(n\) is \(n + n = n\cdot n ?\)

by Scott@TargetTestPrep » Wed May 13, 2020 7:19 am
Vincen wrote: ↑
Mon May 11, 2020 3:28 am
 For how many integers \(n\) is \(n + n = n\cdot n ?\)

a) None
b) One
c) Two
d) Three
e) More than three.

[spoiler]OA=C[/spoiler]

Simplifying the equation, we have:

2n = n^2
n^2 - 2n = 0

n(n - 2) = 0

n = 0 or n = 2

We see that there are two such values.

Answer: C

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage
Top
Post new topic Post Reply
• Page 1 of 1