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cetmk wrote:n x 2^5 x 6^2 x 7^3 can be written as
n x 2^5 x (3 x 2)^2 x 7^3
= n x 2^7 x 3^2 x 7^3
This should contain atleast 2 factors of 5 (5^2) and 3 factors of 3(3^3). Since the number already has 2 factors of 3, the smallest possible value of n is 5^2 x 3 = 75
prime factorizehoustonrockets16 wrote:If both 5^2 and 3^3 are factors of n x 2^5 x 6^2 x 7^3 , what is the smallest possible positive value of n?
A) 25
B) 27
C) 45
D) 75
E) 125
Thanks for the quick reply. My first language is not English and I think the problem is not that I don't get the math but that I don't understand what is asked. The question doesn't make sense to me at all. Maybe you or someone has another question with the same problem which I can try to solve. I'm starring blind on this one.MBA.Aspirant wrote: prime factorize
n x 2^5 x 6^2 x 7^3
n x 2^5 x (2^2 x 3^2) x 7^3
since 3^3 and 5^2 are factors of this, and 3^2 is also included in it, then what remains is 3 and 5^2
so n = 3 * 5^2 = 75
