Let's the image.

We have to find out the area of CABF'EC.
Area of CABF'EC = Area of ABCD - Area of CEFD + Area of DF'F
Area of ABCD = 625 (given)
Area of CEFD = 500 (given)
To get the area of DF'F, we need the values of DF' and F'F.
Area of CEFD = CD * F'D = √625 *F'D = 25F'D = 500 => F'D = 500/25 = 20
Thus, F'F = √(25^2 - 20^2) = 15
Thus, area of DF'F = 1/2 * F'D * F'F = 1/2 * 20 * 15 = 150
Area of CABF'EC = Area of ABCD - Area of CEFD + Area of DF'F = 625 - 500 + 150 = 275
The correct answer: E
Hope this helps!
-Jay
_________________
Manhattan Review GRE Prep
Locations: [url=hhttps://www.manhattanreview.id/gre-prep-jakarta/]GRE Classes Jarkarta[/url] | GRE Prep Course Kuala Lumpur | GRE Prep Manila | GRE Prep Course Bangkok | and many more...
Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.













