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If a racehorse runs an average(arithmetic mean) of m miles p

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by alanforde800Maximus » Tue Oct 18, 2016 9:23 pm
If a racehorse runs an average(arithmetic mean) of m miles per race for r races and then runs n miles in its next race, what is the average number of miles the horse has run for the r + 1 races?

a) (rm + n)/r+1
b) (m + n)/r+1
c) (m + n)/r
d) r(m + n)/r+1
e) (m + rn)/r+1

Please assist with above problem.
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by [email protected] » Tue Oct 18, 2016 9:45 pm
Hi alanforde800Maximus,

This question can be solved Algebraically or by TESTing VALUES. Here's how you can use the second method:

IF...
M = 2
R = 3
Then the racecourse ran (2 miles/race)(3 races) = 6 miles

N = 4
So the horse ran 4 miles in that 1 race.

Thus, the average for the 4 races was (10 miles)/(4 races) = 2.5 miles/race

There's only one answer that matches...

Final Answer: A

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by regor60 » Wed Oct 19, 2016 5:33 am
alanforde800Maximus wrote:If a racehorse runs an average(arithmetic mean) of m miles per race for r races and then runs n miles in its next race, what is the average number of miles the horse has run for the r + 1 races?

a) (rm + n)/r+1
b) (m + n)/r+1
c) (m + n)/r
d) r(m + n)/r+1
e) (m + rn)/r+1

Please assist with above problem.

And here's how you solve it algebraically:

The average is defined as the total miles run divided by the number of races, so the total miles run is therefore the number of races multiplied by the average, in this case:

m*r

The one new race adds 1 to r and n to m*r, so the new average is:

(m*r+n)/(r+1)
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by Jeff@TargetTestPrep » Thu Oct 20, 2016 3:58 pm
alanforde800Maximus wrote:If a racehorse runs an average(arithmetic mean) of m miles per race for r races and then runs n miles in its next race, what is the average number of miles the horse has run for the r + 1 races?

a) (rm + n)/r+1
b) (m + n)/r+1
c) (m + n)/r
d) r(m + n)/r+1
e) (m + rn)/r+1

Please assist with above problem.
We are given that a racehorse runs an average (arithmetic mean) of m miles per race for r races and then runs n miles in its next race. We need to determine the average number of miles the horse has run for r + 1 races. Let's plug the given information into the average formula.

average = sum/quantity

Since the racehorse runs an average (arithmetic mean) of m miles per race for r races, the initial sum = mr and the initial quantity is r.

Since the racehorse then runs n miles in its next race, the new sum is mr + n and the new quantity is r + 1.

Thus, the average number of miles that the horse runs for r + 1 races is:

(mr + n)/(r + 1)

Answer: A

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by fiza gupta » Thu Oct 20, 2016 6:09 pm
total miles covered in r number of races: m*r
mile covered in remaining 1 race = n

average = total miles/races
= (mr+n)(r+1)
SO A
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by Matt@VeritasPrep » Fri Oct 28, 2016 12:14 am
If I run m miles per race for r races, I've run r*m miles.

If I run n miles in my next race, I've run another n miles, for a total of r*m + n.

To find the average, divide that mileage by the number of races: (r*m + n) / (r + 1).
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