$$If\ \ −1 < x < 0\ \ and\ \ 0 < y < 1,$$ which of the following has the least value?
$$A.\ \ \frac{x}{y}$$
$$B.\ (x/y)^2$$
$$C.\ \ \frac{x^2}{y}$$
$$D.\ \ \frac{x^3}{y}$$
$$E.\ \frac{x^2}{y^3}$$
The OA is A.
I know the answer. I just have one confusion as to how a negative sign to the power 3 could be greater than the negative sign to the power 1. Just as in this question it is implied that -x <-x^3. If you do it simply isn't -3 > (-3)^3.
Kindly can any expert help clarify my confusion. Thanks!
$$A.\ \ \frac{x}{y}$$
$$B.\ (x/y)^2$$
$$C.\ \ \frac{x^2}{y}$$
$$D.\ \ \frac{x^3}{y}$$
$$E.\ \frac{x^2}{y^3}$$
The OA is A.
I know the answer. I just have one confusion as to how a negative sign to the power 3 could be greater than the negative sign to the power 1. Just as in this question it is implied that -x <-x^3. If you do it simply isn't -3 > (-3)^3.
Kindly can any expert help clarify my confusion. Thanks!
