$$Compound\ interest\ =\ p\left(1+\frac{r\%}{n}\right)^{nt}$$
$$where\ p=principal\ =\ $3000$$
$$r=rate\ =\ 6\%$$
$$n=\ number\ of\ times\ interest\ is\ compounded\ =\ 12$$
$$t=time\ /year\ =\ 1$$
$$compound\ interest\ =\ 3000\left(1+\frac{6}{100}\cdot\frac{1}{12}\right)^{12}$$
$$\ \ 3000\left(1+\frac{6}{1200}\right)^{12}$$
$$\ \ 3000\cdot1.005^{12}$$
$$\ \ 3000\cdot1.0617$$
$$$3185.1$$
$$Answer\ =\ C$$