KEY CONCEPT: In order to minimize the value of y, we must minimize the value of (x -3)²M7MBA wrote:If \(y= 4 + (x - 3)^2,\) then \(y\) is lowest when \(x =\)
A. 14
B. 13
C. 0
D. 3
E. 4
We know that (some number)² ≥ 0
So, the SMALLEST possible value of (some number)² is 0
Likewise, the SMALLEST possible value of (x -3)² is 0
(x -3)² = 0 when x = 3
Answer: D
Cheers,
Brent
















