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by [email protected] » Sun Oct 22, 2017 10:59 am
Hi LUANDATO,

One of the basic algebraic 'steps' that you'll have to go through on several Quant questions on Test Day is "combine like terms"; here we can combine like terms on each side of the given equation:

2K - 9 - K = 4K+ 6 - 3K
K - 9 = K + 6

As it stands, there is NO solution to this equation - going through one more step would give us:
0 = 15

Final Answer: D

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by EconomistGMATTutor » Sun Oct 22, 2017 12:57 pm
For what value(s) of k is the following equation satisfied: 2k-9-k = 4k+6-3k

a. -5
b. 0 only
c. 5/2 only
d. No value
e. Any value

The OA is D.

Can any expert explain this PS question please? Thanks.
Hi LUANDATO,
Let's take a look at your question.

$$2k-9-k=4k+6-3k$$
$$2k-k+9=4k-3k+6$$
$$k+9=k+6$$
$$k+9-k=6$$
$$k-k=6+9$$
$$0=15$$

Which means, k has no value.
Therefore, option D is correct.

Hope it helps.
I am available if you'd like any follow up.
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by Scott@TargetTestPrep » Wed Nov 20, 2019 5:58 pm
BTGmoderatorLU wrote:For what value(s) of k is the following equation satisfied: 2k-9-k = 4k+6-3k

a. -5
b. 0 only
c. 5/2 only
d. No value
e. Any value

The OA is D.

Can any expert explain this PS question please? Thanks.
Simplifying, we have:

2k - 9 - k = 4k + 6 - 3k

k - 9 = k + 6

We see that there are no values of k for which k - 9 = k + 6.

Answer: D

Scott Woodbury-Stewart
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