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If 4<=x<=6 and 2<=y<=3, then

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If 4<=x<=6 and 2<=y<=3, then

by fskilnik@GMATH » Thu Feb 14, 2019 10:49 am

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A

B

C

D

E

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Answer: [spoiler] ____(D)__[/spoiler]
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
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Source: — Problem Solving |

fskilnik@GMATH wrote:Image
$$?\,\, = \,\,\min \,\left| {\left( {y - x} \right)\left( {y + x} \right)} \right|\,\, = \,\,\min \,\left| {{y^2} - {x^2}} \right|$$
$$\eqalign{
& 2 \le y \le 3\,\,\,\,\, \Rightarrow \,\,\,\,\,4 \le {y^2} \le 9 \cr
& 4 \le x \le 6\,\,\,\,\, \Rightarrow \,\,\,\,\,16 \le {x^2} \le 36\,\,\,\,\, \Rightarrow \,\,\,\,\, - 36 \le - {x^2} \le - 16 \cr} $$
$$\left. \matrix{
4 \le {y^2} \le 9 \hfill \cr
- 36 \le - {x^2} \le - 16\,\,\, \hfill \cr} \right\}\,\,\,\mathop \Rightarrow \limits^{\left( + \right)} \,\,\, - 32 \le {y^2} - {x^2} \le - 7\,\,\,\,\, \Rightarrow \,\,\,\,\,7 \le \left| {{y^2} - {x^2}} \right| \le 32\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,? = 7$$

The correct answer is (D).


We follow the notations and rationale taught in the GMATH method.

Regards,
Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
English-speakers :: https://www.gmath.net
Portuguese-speakers :: https://www.gmath.com.br
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