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There are 10 children in a company's day-care center, and a

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by Jay@ManhattanReview » Fri Aug 09, 2019 1:07 am
swerve wrote:There are 10 children in a company's day-care center, and a pair of children is to be selected to play a game. At most, how many different pairs are possible?

A. 100
B. 90
C. 50
D. 45
E. 25

The OA is D

Source: GMAT Prep
A pair of children means that we have to select 2 children out of 10. Thus, the number of different pairs possible = 10C2 = (10.9) / (1.2) = 45

The correct answer: D

Hope this helps!

-Jay
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by Scott@TargetTestPrep » Sun Aug 11, 2019 6:46 pm
swerve wrote:There are 10 children in a company's day-care center, and a pair of children is to be selected to play a game. At most, how many different pairs are possible?

A. 100
B. 90
C. 50
D. 45
E. 25

The OA is D

Source: GMAT Prep
The number of possible pairs is 10C2 = (10 x 9)/2! = 45.

Answer: D

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