BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Co-ordinate Geometry~~

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 146
Joined: Wed Aug 27, 2008 5:41 am
Thanked: 3 times
by apoorva.srivastva » Sat Feb 20, 2010 2:07 am
line m and n pass through point (1,2). Is the slope of m greater than the slope of n?

1.) the x-intercept of m is greater than 1 and that of n is less than 1

2.) the y-intercept of m = 4 and that of n = (-2)

OA is D

kindly explains to solve st1 algebraically!!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Data Sufficiency |
User avatar
Legendary Member
Posts: 1560
Joined: Tue Nov 17, 2009 2:38 amFollowed by: 5 members
Thanked: 137 times

by thephoenix » Sat Feb 20, 2010 3:11 am
apoorva.srivastva wrote:line m and n pass through point (1,2). Is the slope of m greater than the slope of n?

1.) the x-intercept of m is greater than 1 and that of n is less than 1

2.) the y-intercept of m = 4 and that of n = (-2)

OA is D

kindly explains to solve st1 algebraically!!

slope is nothing but the angle a lin subtends to Xaxis its the angle from X axis towards Y axis

s1) the two line will be as attched

clearly slope of m> slope of n
s2) the two line will be as attached

clearly slope of m>slope n
Attachments
slope.doc
(26 KiB) Downloaded 133 times
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 194
Joined: Thu Jan 14, 2010 5:18 am
Thanked: 2 times

by girish3131 » Sat Feb 20, 2010 5:29 am
@Apoorva


Acc to me, ans is either C or E (will confirm tmrw b/w them)

but am damn sure that Ans can't be D

U to plz check again.

Thanks!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1132
Joined: Mon Jul 20, 2009 3:38 amFollowed by: 6 members
Location: India
Thanked: 64 times
GMAT Score:760

by harsh.champ » Sat Feb 20, 2010 5:52 am
apoorva.srivastva wrote:line m and n pass through point (1,2). Is the slope of m greater than the slope of n?

1.) the x-intercept of m is greater than 1 and that of n is less than 1

2.) the y-intercept of m = 4 and that of n = (-2)

OA is D

kindly explains to solve st1 algebraically!!
Here is the algebraic explanation:-
Let the line be y=mx +c and y=nx+d
Now putting point(1,2) we get
2=m+c and 2 = n+d
or c=2-m and d=2-n

Statement 1:- x-intercept means y=0
For m we have x= -c/m > 1
For n we have x= -d/n<1
Putting values of c and d from above,we have
(m-2)/m >1 and (n-2)/n < 1
Transposing 1 on the L.H.S.,we get
=>-2/m > 0 and -2/n <0

Since we don't know whether m and n are both +ve or both -ve or have alternate signs we can't tell anything.
Hence,the statement is insufficient.

I hope the above algebraic explanation helps. :)
It takes time and effort to explain, so if my comment helped you please press Thanks button :)



Just because something is hard doesn't mean you shouldn't try,it means you should just try harder.

"Keep Walking" - Johnny Walker :P
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 146
Joined: Wed Aug 27, 2008 5:41 am
Thanked: 3 times

by apoorva.srivastva » Sat Feb 20, 2010 7:54 am
girish3131 wrote:@Apoorva


Acc to me, ans is either C or E (will confirm tmrw b/w them)

but am damn sure that Ans can't be D

U to plz check again.

Thanks!
Girish i checked it bro..OA is D :)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 146
Joined: Wed Aug 27, 2008 5:41 am
Thanked: 3 times

by apoorva.srivastva » Sat Feb 20, 2010 7:57 am
@ harsh...i too feel the st1 is insufficient!!
st2 is sufficient

@ girish....for me the OA should be B!!

someone can u please diagnose the this particular DS ;)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1132
Joined: Mon Jul 20, 2009 3:38 amFollowed by: 6 members
Location: India
Thanked: 64 times
GMAT Score:760

by harsh.champ » Sat Feb 20, 2010 8:27 am
apoorva.srivastva wrote:@ harsh...i too feel the st1 is insufficient!!
st2 is sufficient

@ girish....for me the OA should be B!!

someone can u please diagnose the this particular DS ;)
line m and n pass through point (1,2). Is the slope of m greater than the slope of n?

1.) the x-intercept of m is greater than 1 and that of n is less than 1

2.) the y-intercept of m = 4 and that of n = (-2)


Ok.I will show it step-by-step
Let the line be y=mx +c and y=nx+d
Now putting point(1,2) we get
2=m+c and 2 = n+d
or c=2-m and d=2-n

From St 2:-
the y-intercept(means x=0) of m = 4,hence we have c = 4
Also,y-intercept of n = (-2) ,hence we have d = -2
But,still we don't know about their slopes m and n(we only have their intercepts c and d)
Hence St 2 is insufficient.

So, the answer cannot be B.
It takes time and effort to explain, so if my comment helped you please press Thanks button :)



Just because something is hard doesn't mean you shouldn't try,it means you should just try harder.

"Keep Walking" - Johnny Walker :P
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1132
Joined: Mon Jul 20, 2009 3:38 amFollowed by: 6 members
Location: India
Thanked: 64 times
GMAT Score:760

by harsh.champ » Sat Feb 20, 2010 8:30 am
apoorva.srivastva wrote:
someone can u please diagnose the this particular DS ;)
Now I am posting the soln. approach that I think you might have taken:-

2=m+c and 2 = n+d
or c=2-m and d=2-n
the y-intercept of m = 4,hence we have -c/m = 4(This is when x-intercept is 4)
=>c=-4m
Also,y-intercept of n = (-2) ,hence we have -d/n = -2(This is when x-intercept is -2)
=>d=2n
Putting values of c and d from above,we have
c=2 - m and c=-4m
=>m= -2/3
Also,d=2-n and d=2n
=>n=2/3
Hence,we get the slopes.
I think when you solved the 2nd statement ,the brain did not switch from x-intercept mode to y-intercept mode and hence you solved it by the incorrect method as I have shown.

I hope now you understand the trap in the question.

Hope this illustration will help u apoorva to diagnose this DS. :)
It takes time and effort to explain, so if my comment helped you please press Thanks button :)



Just because something is hard doesn't mean you shouldn't try,it means you should just try harder.

"Keep Walking" - Johnny Walker :P
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 610
Joined: Fri Jan 15, 2010 12:33 amFollowed by: 2 members
Thanked: 47 times

by kstv » Sat Feb 20, 2010 10:51 am
The lines m and n insertect at (1,2).

(1) m intersect the x axis at > 1 , say (2,0) . It has a - ve slope.

Line n passes the point (1,2) and intersect x axis at , 1 , say 0.5. It hass +ve slope.

Sufficient.

(2) the y intercept of m = 4 and that of n is -2 .

If two points are known the eq. y = mx +c can be solved.

Sufficient
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1