BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Hypotenuse of Triangle?

Expert replies
by bml1105 » Thu Jun 05, 2014 1:40 pm
The perimeter of a certain isosceles right triangle is 16 + 16(sqrroot 2). What is the length of the hypotenuse of the triangle?

(A) 8
(B) 16
(C) 4(sqrroot 2)
(D) 8(sqrroot 2)
(E) 16(sqrroot 2)

OA: B
Join the discussion
Source: — Problem Solving |

by Brent@GMATPrepNow » Thu Jun 05, 2014 1:43 pm
The Perimeter of a certain isosceles right triangle is 16 + 16√2. What is the length of the hypotenuse of the triangle?

A) 8
B) 16
C) 4√2
D) 8√2
E) 16√2
An IMPORTANT point to remember is that, in any isosceles right triangle, the sides have length x, x, and x√2 for some positive value of x.

Note: x√2 is the length of the hypotenuse, so our goal is to find the value of x√2

From here, we can see that the perimeter will be x + x + x√2

In the question, the perimeter is 16 + 16√2, so we can create the following equation:
x + x + x√2 = 16 + 16√2,
Simplify: 2x + x√2 = 16 + 16√2
IMPORTANT: Factor x√2 from the left side to get : x√2(√2 + 1) = 16 + 16√2
Now factor 16 from the right side to get: x√2(√2 + 1) = 16(1 + √2)
Divide both sides by (1 + √2) to get: x√2 = 16

Answer = B

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by GMATGuruNY » Thu Jun 05, 2014 1:54 pm
The perimeter of a certain isosceles right triangle is 16 + 16√2. What is the length of the hypotenuse?
a. 8
b. 16
c. 4√2
d. 8√2
e. 16√2
The sides of an isosceles right triangle are in the following ratio: s : s : s√2.
So if s=side and h=hypotenuse, then h = s√2 and s = h/√2.

We can plug in the answers, which represent the length of the hypotenuse.

Answer choice C: h = 4√2
s = (4√2)/√2 = 4.
p = 4 + 4 + 4√2 = 8 + 4√2.
Eliminate C. The perimeter needs to be quite a bit larger.

Answer choice B: h = 16
s = 16/√2 = (16*√2)/(√2*√2) = (16√2)/2 = 8√2.
p = 8√2 + 8√2 + 16 = 16 + 16√2. Success!

The correct answer is B.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by [email protected] » Thu Jun 05, 2014 3:48 pm
Hi bml1105,

Mitch's approach to TEST THE ANSWERS is perfect for this scenario. There's a Number Property about Isosceles triangles that will help you to avoid most of the wrong answers...

The ratio of sides in an Isosceles Triangle is: x, x, and x√2

If, for example, one of the "short sides" was 5, then we'd have 5, 5, 5√2 and the perimeter would be 10 + 5√2. Notice that the 10 and 5 are different numbers....That will ALWAYS happen IF the short side is an integer and the hypotenuse has a √2 attached to it....

We're given a perimeter of 16 + 16√2; here, both numbers are 16, so we are NOT dealing with the above scenario. The "short sides" CANNOT be integers and the hypotenuse CANNOT have a √2 attached to it. Eliminate C, D and E.

From there, we can TEST A and B to find the match.

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion

by bml1105 » Thu Jun 05, 2014 5:59 pm
Brent@GMATPrepNow wrote:
In the question, the perimeter is 16 + 16√2, so we can create the following equation:
x + x + x√2 = 16 + 16√2,
Simplify: 2x + x√2 = 16 + 16√2
IMPORTANT: Factor x√2 from the left side to get : x√2(√2 + 1) = 16 + 16√2
Now factor 16 from the right side to get: x√2(√2 + 1) = 16(1 + √2)
Divide both sides by (1 + √2) to get: x√2 = 16
Hi Brent,

I'm a little confused. How can we factor out x√2 from 2x + x√2 and get x√2(√2 + 1) when the 2x doesn't have an x√2. If anything wouldn't it be 2x/x√2 (√2/√2) = (2√2)/2?
Join the discussion

by bml1105 » Thu Jun 05, 2014 6:01 pm
Thanks Rich, I was definitely confused because I was trying to use x:x:x√2 and I couldn't understand how it could work so I panicked!
Join the discussion

by Brent@GMATPrepNow » Thu Jun 05, 2014 6:21 pm
bml1105 wrote:
Hi Brent,

I'm a little confused. How can we factor out x√2 from 2x + x√2 and get x√2(√2 + 1) when the 2x doesn't have an x√2. If anything wouldn't it be 2x/x√2 (√2/√2) = (2√2)/2?
Good question.
Notice that 2 = (√2)(√2)
So, let's start at the point where we have: 2x + x√2 = 16 + 16√2
We can rewrite this as (√2)(√2)x + x√2 = 16 + 16√2
So, on the left side, both terms have an x and a √2
So we can factor x√2 from the left side to get : x√2(√2 + 1) = 16 + 16√2

I hope that helps.

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by garmahis » Tue Jun 10, 2014 6:10 am
I'm so disappointed of myself. I tried to answer the problem but couldn't get the answer from the choices. Hmmmmn. Maybe I should start reviewing on how to get the hypotenuse of a triangle. Should have been an easy question since it's been taught all over from high school to college. Thanks for the explanations you've provided here. I am enlightened as well. Thanks for posting the question too. It was mind-boggling and tickled the brain cells in me. Best of luck to all test takers. Especially on the Math section. This section proved to be the most challenging for me.

-Garmahis
CheatSheetOne
All GMAT Math Formulas you need to succeed!
Join the discussion

by Brent@GMATPrepNow » Tue Jun 10, 2014 7:15 am
Don't be too hard on yourself, Garmahis. This is a tricky question. In fact, I'd put it in the 700 range (difficulty-wise).

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion