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[email protected]
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Request that the experts also explain the concept, thanks
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Anju@Gurome
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In GMAT, always try to draw the figure while solving coordinate geometry problems.[email protected] wrote:In the rectangular coordinate system above, the line y = x is the perpendicular bisector of segment AB (not shown), and the x-axis is the perpendicular bisector of
segment BC (not shown). If the coordinates of point A are (2,3), what are the coordinates of point C ?
(A) (-3,-2)
(B) (-3,2)
(C) (2,-3)
(D) (3,-2)
(E) (2,3)
Refer to the figure below,
The line y = x is the perpendicular bisector of segment AB, so the point B is the mirror reflection of point A around the line y = x, so its coordinates are (3, 2). In the same way, since the x-axis is the perpendicular bisector of segment BC then the point C is the mirror reflection of point B around the x-axis, so its coordinates are (3, -2).
The correct answer is D.
Anju Agarwal
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GMATGuruNY
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Just draw a picture of what is being described. A perpendicular bisector:In the rectangular coordinate system above, the line
y = x is the perpendicular bisector of segment AB (not
shown), and the x-axis is the perpendicular bisector of
segment BC (not shown). If the coordinates of point A
are (2,3), what are the coordinates of point C ?
(A) (-3,-2)
(B) (-3,2)
(C) (2,-3)
(D) (3,-2)
(E) (2,3)
-- intersects at the midpoint
-- forms a right angle
Here's my rudimentary drawing:
Looking at the drawing above, we can see that point C must have a positive x-coordinate and a negative y-coordinate.
Eliminate A, B and E.
Since point C is further to the right than is point A, the x-coordinate of point C must be greater than 2.
Eliminate C.
The correct answer is D.
Check here for a similar problem:
https://www.beatthegmat.com/grockit-toug ... 74452.html
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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