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If a set consists of all positive digits less than or

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If a set consists of all positive digits less than or

by VJesus12 » Mon May 28, 2018 1:46 am

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If a set consists of all positive digits less than or equal to 3 and of the squares of those digits, what is the mode of the set?

A. 1
B. 2
C. 3
D. 4
E. 9

The OA is the option A.

Why is A the correct choice? How can show it? I'd appreciate some help here. Please.
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answer

by Vincen » Mon May 28, 2018 2:51 am
Hello Vjesus12.

Let's take a look at your question.

Since the set consists of 1, 2, 3 and their squares, then the set is the following: A = {1, 2, 3, 1, 4, 9}.

Now, the mode of a set is the element that most appear on it, hence we have that the mode of the set A is 1.

This is why the correct answer is the option A.

I hope this can help you.
Last edited by Vincen on Mon May 28, 2018 3:12 am, edited 1 time in total.
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by GMATGuruNY » Mon May 28, 2018 2:58 am
VJesus12 wrote:If a set consists of all positive digits less than or equal to 3 and of the squares of those digits, what is the mode of the set?

A. 1
B. 2
C. 3
D. 4
E. 9
The MODE of a set is the number that appears the most often.

Positive digits less than or equal to 3:
1, 2, 3.
Squares of these digits:
1, 4, 9.
Resulting set when the two lists above are combined:
1, 1, 2, 3, 4, 9.
In the resulting set, the number that appears the most often is 1.

The correct answer is A.
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by Jeff@TargetTestPrep » Wed May 30, 2018 4:21 pm
VJesus12 wrote:If a set consists of all positive digits less than or equal to 3 and of the squares of those digits, what is the mode of the set?

A. 1
B. 2
C. 3
D. 4
E. 9
The set consists of the following integers: 1, 2, 3, 1^2 = 1, 2^2 = 4 and 3^2 = 9. So the mode is 1.

Answer: A

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Head of GMAT Instruction
[email protected]

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