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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## How many numbers between 1 and 200, inclusive, have a 2 in tagged by: Max@Math Revolution ##### This topic has 3 expert replies and 0 member replies ### GMAT/MBA Expert ## How many numbers between 1 and 200, inclusive, have a 2 in ## Timer 00:00 ## Your Answer A B C D E ## Global Stats Difficult [GMAT math practice question] How many numbers between 1 and 200, inclusive, have a 2 in the units place and are divisible by 4? A. 8 B. 9 C. 10 D. 11 E. 12 _________________ Math Revolution Finish GMAT Quant Section with 10 minutes to spare. The one-and-only Worldâ€™s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. Only$149 for 3 month Online Course
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Max@Math Revolution wrote:
[GMAT math practice question]

How many numbers between 1 and 200, inclusive, have a 2 in the units place and are divisible by 4?

A. 8
B. 9
C. 10
D. 11
E. 12
An integer is divisible by 4 if its last two digits form a multiple of 4.
Two-digit multiples of 4 with a units digit of 2:
12, 32, 52, 72, 92
Since the last two digits must be one of the options above, between 1 and 200 there are 10 integers that have a units digit of 2 and are divisible by 4:
12, 32, 52, 72, 92
112, 132, 152, 172, 192

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Max@Math Revolution wrote:
[GMAT math practice question]

How many numbers between 1 and 200, inclusive, have a 2 in the units place and are divisible by 4?

A. 8
B. 9
C. 10
D. 11
E. 12
The numbers are 12, 32, 52, etc. We see that the first number is 12 and the last number will be 192 and the numbers form an arithmetic progression with a common difference of 20. Therefore, there are (192 - 12)/20 + 1 = 180/20 + 1 = 9 + 1 = 10 such numbers.

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In order for a number with 2 in the units place to be divisible by 4, the last two digits must be one of 12, 32, 52, 72 and 92.
Thus, the numbers between 1 and 200, inclusive, satisfying this property are
12, 32, 52, 72, 92, 112, 132, 152 and 172.

There are 8 such numbers. Therefore, A is the answer.

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