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How many arrangements of the letters ‘s’, ‘u’, ‘câ

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by Max@Math Revolution » Tue Feb 13, 2018 12:36 am
[GMAT math practice question]

How many arrangements of the letters 's', 'u', 'c', 'c', 'e', 's', 's' in a straight line are possible?

A. 60
B. 120
C. 180
D. 240
E. 420
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by Max@Math Revolution » Thu Feb 15, 2018 3:34 am
=>

The seven letters 's', 'u', 'c', 'c', 'e', 's', 's' include three s's and two c's.
The number of permutations is 7! / (3!*2!) = 420.

Therefore, the answer is E.

Answer: E
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