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If 27^(4x + 2)*162^(-2x)*36^x*9^(6-2x)=1, x=?
A. -9
B. -6
C. 3
D. 6
E. 9
27^(4x + 2)*162^(-2x)*36^x*9^(6-2x)=(3)^3(4x + 2) * (2*3^4)^(-2x) * (2*3)^2x * (3)^2(6-2x)=1
3^(12x + 6) * 2^(-2x) * 3^(-8x) * 2^(2x) * 3^(2x) * 3^(12 - 4x) = 1
==> "‹3^(12x + 6 - 8x + 2x + 12 - 4x) * 2^(-2x + 2x) = 1 ==> 3^(2x+18)*2^0=1 ==> 3^(2x+18)=1, 2x+18=0, x=-9. therefore the answer is A
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