I go with 75:
Given X = (some integer *Y) + 9 and X = 96Y + 0.12Y.
Equate both and you get 0.12Y = 9 => Y=75.
Can anyone please help with this one?
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cramya
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Vishu,
Consider 5/3 = 1 + 2/3
x=5,y=3 Quotient = 1 remiander = 2
i.e. x/y = Quotient+Remainder / y (1)
x/y = 96 + .12
.12 is not the remainder but by the equztion (1) is equal to 9/y
9/y = .12
y=75
FYI:
If we have to find x then BY EQUATION (1)
x = y (Quotient+remainder/y)
x = 75(96+9/75)
= 7209
CHECK: 7209/75 = 96.12
Hope this helps!
Consider 5/3 = 1 + 2/3
x=5,y=3 Quotient = 1 remiander = 2
i.e. x/y = Quotient+Remainder / y (1)
x/y = 96 + .12
.12 is not the remainder but by the equztion (1) is equal to 9/y
9/y = .12
y=75
FYI:
If we have to find x then BY EQUATION (1)
x = y (Quotient+remainder/y)
x = 75(96+9/75)
= 7209
CHECK: 7209/75 = 96.12
Hope this helps!

















