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TRIANLGE!!

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TRIANLGE!!

by marmar29 » Wed Aug 17, 2011 2:52 pm
hello
i need help in a method how to calculate the side of triangle if vertices are given!!
here an example
in tri. abc .. c(4,-4),,b (-3,-3),, a(5,5)so bc is
A) 7.07
B)8.08
c) 9.09
d)10.10
e) 11.11
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by MBA.Aspirant » Wed Aug 17, 2011 4:08 pm
use the distance formula:

distance between B (x1,y1) and C (x2,y2) = √ [(y2-y1)^2 + (x2-x1)^2]

given two points B (-3,-3) and C (4,-4)

BC = √ (-4-(-3))^2 + (4- (-3))^2

= √50

= 7.07
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