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You can write 384 as 128*3 or 2^7*3sushil hande wrote:HCF of 384 & a^5b^2 is 16ab.what is the correct relation between a and b?
Any conditions given for what a and b are? If a and b are prime,gauri14 wrote:I tried solving this question even with the little hint given but still don't know how to proceed.
If it helps the options given for this question are as follows -
1) a = 2b
2) a + b =3
3) a - b = 3
4) a + b = 5
No special condition for a and b. The answer for this is 5 like you've shown. Thanks for the help!jaetpu wrote:Any conditions given for what a and b are? If a and b are prime,gauri14 wrote:I tried solving this question even with the little hint given but still don't know how to proceed.
If it helps the options given for this question are as follows -
1) a = 2b
2) a + b =3
3) a - b = 3
4) a + b = 5
prime factorization of 384 = 2^7 * 3, 16ab is 2^4*a*b. Thus a and b must be 3 and 2 (in either order). a+b=5
