All the numbers are in 10s so divisible by 5 (prime no) and 2 . Divide by 10
A) 20 & 60 2 6
(B) 20 & 80 2 8
(C) 30 & 60 3 6
(D) 40 & 80 4 8
(E) 50 & 100 5 10
Only 8 is 2³ two more factos then 2

kstv wrote:All the numbers are in 10s so divisible by 5 (prime no) and 2 . Divide by 10
A) 20 & 60 2 6
(B) 20 & 80 2 8
(C) 30 & 60 3 6
(D) 40 & 80 4 8
(E) 50 & 100 5 10
Only 8 is 2³ two more factos then 2

I didn't get your point here. What is your answer?

IMO B cos
A )6 = 2*3
B) 8 = 2 * 2 * 2 (two more factors)
C) 6 = again 3*2
D) 8 = 4* 2
E ) 10 = 5*2

kstv wrote:IMO B cos
A )6 = 2*3
B) 8 = 2 * 2 * 2 (two more factors)
C) 6 = again 3*2
D) 8 = 4* 2
E ) 10 = 5*2

I guess you misinterpreted something.

sanju09 wrote:Two different numbers have the same prime factors, but one of the numbers has two more factors than the other. Which of the following would correctly represent the two numbers?
(A) 20 & 60
(B) 20 & 80
(C) 30 & 60
(D) 40 & 80
(E) 50 & 100

40 has 8 factors and 80 has 10 . No of prime factors for both of them are 2 ( 2 & 5).

IMO D .

sanju09 wrote:Two different numbers have the same prime factors, but one of the numbers has two more factors than the other. Which of the following would correctly represent the two numbers?
(A) 20 & 60
(B) 20 & 80
(C) 30 & 60
(D) 40 & 80
(E) 50 & 100

IMHO Answer is B

Because

20 = 5 X 2 X 2
80 = 5 X 2 X 2 X 2 X 2 (2 more factors)

All other choices have only one factor extra.

What is the OA ???

[email protected] wrote:

sanju09 wrote:Two different numbers have the same prime factors, but one of the numbers has two more factors than the other. Which of the following would correctly represent the two numbers?
(A) 20 & 60
(B) 20 & 80
(C) 30 & 60
(D) 40 & 80
(E) 50 & 100

IMHO Answer is B

Because

20 = 5 X 2 X 2
80 = 5 X 2 X 2 X 2 X 2 (2 more factors)

All other choices have only one factor extra.

What is the OA ???

Please revise this concept with an example as under:

How to find total number of factors of a number, say 56

Step 1: Break 56 into its primes, like 56 = 2 × 2 × 2 × 7 = 2^3 × 7^1

Step 2: Add 1 to each exponent of the primes, 3 + 1 = 4 and 1 + 1 = 2

Step 3: Multiply the results of Step 2 together, 4 × 2 = 8

Hence, the total number of factors of 56 is 8.

We can count those for 56

1, 2, 4, 7, 8, 14, 28. and 56; out of which exactly two (2 & 7) are prime factors of 56; exactly 6 (2, 4, 7, 8, 14, & 28) are proper factors of 56.

harshavardhanc wrote:

sanju09 wrote:Two different numbers have the same prime factors, but one of the numbers has two more factors than the other. Which of the following would correctly represent the two numbers?
(A) 20 & 60
(B) 20 & 80
(C) 30 & 60
(D) 40 & 80
(E) 50 & 100

40 has 8 factors and 80 has 10 . No of prime factors for both of them are 2 ( 2 & 5).

IMO D .

Same soln.
Agree with D.

Is this a real GMAT Question ?

so whats the correct answer?

OA must be D.
Total number of factors of 40 = 8
Total number of factors of 80 =10.

Both have same prime factors(2 & 5).