HardCover_Books
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- codesnooker
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Using both (1) and (2):
If we say that, total cost of hardcover books that Juan bought $175 and the total cost of books is less than 260 then Juan can not buy more than 10 paperback books. So juan bought 6 Hardcover books.
Choose(c).
If we say that, total cost of hardcover books that Juan bought $175 and the total cost of books is less than 260 then Juan can not buy more than 10 paperback books. So juan bought 6 Hardcover books.
Choose(c).
- codesnooker
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Where does in the question it is written that Juan bought books of $175?Suyog wrote:Using both (1) and (2):
If we say that, total cost of hardcover books that Juan bought $175 and the total cost of books is less than 260 then Juan can not buy more than 10 paperback books. So juan bought 6 Hardcover books.
Choose(c).
In the question it is clearly mention that hardcover books were bought for at least 150$ (So we can't ignore this case).
And suppose, if Hardcover books total price was $150. then amount left = 260 - 150 = 110.
Also it mentioned that total price was less then 260, so paperback books will be 109.99$ at max.
And in this, he can be either 10, 11, 12, or 13 paperback books.
So, in my opinion, answer (E) should be correct.
Let me know if I am doing mistake somewhere.
Thanks
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- Ian Stewart
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The question doesn't ask how many paperback books he bought. It asks how many hardcover books he bought. Suyog's solution is correct; if he spends $175 or more on hardcovers, the other conditions in the question can't be true. So he must have spent $150 on hardcovers - that is, he must have bought 6 hardcover books.codesnooker wrote: And in this, he can be either 10, 11, 12, or 13 paperback books.
You can solve in this waycodesnooker wrote:Any Suggestion?
x is the number of paperback books
y is the number of hardcover books
we have:
the price of a paperback book is $8,
the price of a hardcover book - $25,
x>10
from the (1) we'll get: 25y greater or equal to 150
from the (2): 8x+25y<260
Solving (1), you'll get y greater or equal 6 -----> insuff.
As for (2), we have a set of equations: 8x+25y<260 and x>10. Solving this system, you'll get y<7.2 . So y should be less than 7 -----> insuff.
Statements taking together are suff.: 6<=y<7. So, y should be equal to 6.
The ans. C.
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Can you plz. explain in details how you reached at this $175.Ian Stewart wrote:The question doesn't ask how many paperback books he bought. It asks how many hardcover books he bought. Suyog's solution is correct; if he spends $175 or more on hardcovers, the other conditions in the question can't be true. So he must have spent $150 on hardcovers - that is, he must have bought 6 hardcover books.codesnooker wrote: And in this, he can be either 10, 11, 12, or 13 paperback books.
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Only one thing to object: solving the 8x+25y<260 and x>10 sistem will result in y<6.88, otherwise your explanation allows 2 solutions 6 and 7 (7<7.2).olika wrote:You can solve in this waycodesnooker wrote:Any Suggestion?
x is the number of paperback books
y is the number of hardcover books
we have:
the price of a paperback book is $8,
the price of a hardcover book - $25,
x>10
from the (1) we'll get: 25y greater or equal to 150
from the (2): 8x+25y<260
Solving (1), you'll get y greater or equal 6 -----> insuff.
As for (2), we have a set of equations: 8x+25y<260 and x>10. Solving this system, you'll get y<7.2 . So y should be less than 7 -----> insuff.
Statements taking together are suff.: 6<=y<7. So, y should be equal to 6.
The ans. C.
Regards,
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- Ian Stewart
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Hardcovers cost $25 each. If he buys 7 or more hardcovers, he would spend at least 7*25 = $175. That isn't possible if you use the information from both statements, so he must have bought fewer than 7 hardcovers.gmattester wrote:Can you plz. explain in details how you reached at this $175.Ian Stewart wrote:The question doesn't ask how many paperback books he bought. It asks how many hardcover books he bought. Suyog's solution is correct; if he spends $175 or more on hardcovers, the other conditions in the question can't be true. So he must have spent $150 on hardcovers - that is, he must have bought 6 hardcover books.codesnooker wrote: And in this, he can be either 10, 11, 12, or 13 paperback books.
- codesnooker
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What a silly mistake I did and even post on the forum also. Sorry for the trouble guys. I got it.