bblast wrote:If x is not equal to -y, is (x-y)/(x+y) > 1 ?
1> x>0
2> y<0

Consider the following two cases,

• 1. x = 2 and y = -1 --> (x - y)/(x + y) = 3/1 = 3 > 1
  2. x = 2 and y = -3 --> (x - y)/(x + y) = 5/(-1) = -5 < 1

Both of the above cases satisfy both the statements but in one case the answer is to the main question is YES in other case it is NO. Hence, both statements together is not sufficient to answer the question.

The correct answer is E.

bblast wrote:...I would like to see whether we can algebraically reduce a solution.

The problem can be solved algebraically too, but in that case the solution will be a bit more time consuming.

bblast wrote:Anurag- Could you please share with me an algebraic solution for this as well ?

For x > 0 and y < 0, (x - y) will be always positive.
But (x + y) may be positive or negative and accordingly (x - y)/(x + y) will be greater than 1 or less than 1.

If x > |y|, then (x - y)/(x + y) = (x + |y|)/(x - |y|) > 1
If x < |y|, then (x - y)/(x + y) = (x + |y|)/(x - |y|) < 0 < 1

Hence, both statements together is not sufficient.