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For some reason I am missing how you went from step 3 to step 4 here. How does 2^34 - 2^28 become 2^28(2^6 - 1)?ramyaravindran wrote:You can simplify the above equation as follows
4^17 - 2 ^ 28
(2^2)^17 - 2 ^ 28
2^34 - 2^28
this can be written as
2^28(2^6 - 1)
2^28(64-1)
2^28 * 63 => 2^28*7*3*3
The greatest prime number for the above would be 7. So the answer should be D.
2^34=2^28 * 2^6uncbeers wrote: For some reason I am missing how you went from step 3 to step 4 here. How does 2^34 - 2^28 become 2^28(2^6 - 1)?
Thank you!
