What is the greatest prime factor of 4^14-2^28?
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GREATEST PRIME FACTOR
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Mclaughlin
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ramyaravindran
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Is the question correct?. From how I read the question when you simplify the equation it comes out to be zero. 4^14 - 2^28 => 2^28 -2^28 => 0.
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Mclaughlin
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oh shoot i'm sorry, i typed it wrong. heres the right question...
What is the greatest prime factor of 4^17-2^28?
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What is the greatest prime factor of 4^17-2^28?
2
3
5
7
11
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ramyaravindran
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You can simplify the above equation as follows
4^17 - 2 ^ 28
(2^2)^17 - 2 ^ 28
2^34 - 2^28
this can be written as
2^28(2^6 - 1)
2^28(64-1)
2^28 * 63 => 2^28*7*3*3
The greatest prime number for the above would be 7. So the answer should be D.
4^17 - 2 ^ 28
(2^2)^17 - 2 ^ 28
2^34 - 2^28
this can be written as
2^28(2^6 - 1)
2^28(64-1)
2^28 * 63 => 2^28*7*3*3
The greatest prime number for the above would be 7. So the answer should be D.
For some reason I am missing how you went from step 3 to step 4 here. How does 2^34 - 2^28 become 2^28(2^6 - 1)?ramyaravindran wrote:You can simplify the above equation as follows
4^17 - 2 ^ 28
(2^2)^17 - 2 ^ 28
2^34 - 2^28
this can be written as
2^28(2^6 - 1)
2^28(64-1)
2^28 * 63 => 2^28*7*3*3
The greatest prime number for the above would be 7. So the answer should be D.
Thank you!
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pepeprepa
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2^34=2^28 * 2^6uncbeers wrote: For some reason I am missing how you went from step 3 to step 4 here. How does 2^34 - 2^28 become 2^28(2^6 - 1)?
Thank you!
a^(b+c)= a^b * a^c
So we have
A= 2^34 - 2^28
A= 2^28 * 2^6 - 2^28
A= 2^28 ( 2^6 -1)
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sanju09
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4^17 = (2^2)^17 = 2^34
2^34 - 2^28 = 2^28*(2^6 - 1) = 2^28*63 = 2^28 * 7 * 3^2
so 7
2^34 - 2^28 = 2^28*(2^6 - 1) = 2^28*63 = 2^28 * 7 * 3^2
so 7
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Sanjeev K Saxena
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www.manyagroup.com
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anthony.j
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Ahhh.... I finally figured it out after writing it down on paper. You turned 2^34 into two number 2^6 and 2^28. Now the two 2^28 cancel each out out leaving 2^1 * 2^6
The rest is just simplifying.
Thanks!
The rest is just simplifying.
Thanks!
