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by knight247 » Thu Sep 15, 2011 8:50 am
Set A consists of integers -9, 8, 3, 10, and J; Set B consists of integers -2, 5, 0, 7, -6, and T. If R is the median of Set A and W is the mode of set B, and R^W is a factor of 34, what is the value of T if J is negative?
(A) -2
(B) 0
(C) 1
(D) 2
(E) 5

OA is B
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by cans » Thu Sep 15, 2011 8:59 am
A:{-9,3,8,10,J}
B:{-6,-2,0,5,7,T}
if J is negative,R = 3 (Median of A)
3^W is factor of 34. (34 doesn't have 3 as prime factor)
Thus W=0 (1 is factor of 34)
Thus as 0 is mode, T=0
IMO B
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by sl750 » Thu Sep 15, 2011 9:32 am
A={-9,8,3,10,J}
B={-2,5,0,7,-6,T}

As J is negative, it could appear as the first number or the second number in set A when arranged in ascending order. Either way, 3 is the median. So W=3

Factors of 34 = 17*2. The only power of 3^W that divides in to 34 evenly is W=0. As W represents the mode of set B, T has to be 0
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