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Source: — Data Sufficiency |
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by 4meonly » Tue Aug 19, 2008 11:35 pm
About question 3
I’ll mark even as E, odd – as O.
(1)
x(y+5) – even.
Means that
a. x and y+5 are both E, making y O
b. x-E, y+5=O, making y-E
c. x-O, y+5=E, making y O
x can be as O as E – INSUFFICIENT

(2)
6y^2+4y+25 = E
Means that 6y^2+4y = O
factorizing y we get y(6y+4) = O
6y+4 is obviously E, this means that y is O
But nothing about x….– INSUFFICIENT


(1) and (2)
From (2) we know that y is Even.
From (1) we know that to make x(y+5) even x can be as E (from a.) as O (from c.)
So, INSUFFICIENT

Answer is E.
Here E doesn’t mean Even :D
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by 4meonly » Tue Aug 19, 2008 11:44 pm
About the 1st question:
From the table is can deduce that to make 130 cents we should by only 1 combination - 2*23 cents+4*21cents=130 cents.
Because from the main statement we know that we have nly 6 pencils.

Thats why (2) in SUFFicient making B the right answer

About 2nd question - no idea, too :(
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by sharad » Wed Aug 20, 2008 12:58 am
Question 3

using 2)
The quadratic equation will be even under following condition
6y2 (always even) + 25 (odd) + 41y (this needs to be odd, hence y cannot be even)
So get y is odd

From 1) x(y+5)
y+5 is even hence even . (x, even or odd) will give x(y+5) as even

hence, even using both the statement you it is not possible to determine if x is odd or even hence E
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by ajmoney09 » Wed Aug 20, 2008 7:05 am
4meonly wrote:About the 1st question:
From the table is can deduce that to make 130 cents we should by only 1 combination - 2*23 cents+4*21cents=130 cents.
Because from the main statement we know that we have nly 6 pencils.

Thats why (2) in SUFFicient making B the right answer

About 2nd question - no idea, too :(
But it does not say we have 6 pencils in the stem, it just says she bought some pencils we do not know she bough 6 pencils until statement 1.
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by ajmoney09 » Wed Aug 20, 2008 7:07 am
sharad wrote:Question 3

using 2)
The quadratic equation will be even under following condition
6y2 (always even) + 25 (odd) + 41y (this needs to be odd, hence y cannot be even)
So get y is odd

From 1) x(y+5)
y+5 is even hence even . (x, even or odd) will give x(y+5) as even

hence, even using both the statement you it is not possible to determine if x is odd or even hence E
Thanks for this. Made sense.
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by ajmoney09 » Wed Aug 20, 2008 7:08 am
4meonly wrote:About question 3
I’ll mark even as E, odd – as O.
(1)
x(y+5) – even.
Means that
a. x and y+5 are both E, making y O
b. x-E, y+5=O, making y-E
c. x-O, y+5=E, making y O
x can be as O as E – INSUFFICIENT

(2)
6y^2+4y+25 = E
Means that 6y^2+4y = O
factorizing y we get y(6y+4) = O
6y+4 is obviously E, this means that y is O
But nothing about x….– INSUFFICIENT


(1) and (2)
From (2) we know that y is Even.
From (1) we know that to make x(y+5) even x can be as E (from a.) as O (from c.)
So, INSUFFICIENT

Answer is E.
Here E doesn’t mean Even :D
Thanks man. :D
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by 4meonly » Wed Aug 20, 2008 8:26 am
ajmoney09 wrote:
4meonly wrote:About the 1st question:
From the table is can deduce that to make 130 cents we should by only 1 combination - 2*23 cents+4*21cents=130 cents.
Because from the main statement we know that we have nly 6 pencils.

Thats why (2) in SUFFicient making B the right answer

About 2nd question - no idea, too :(
But it does not say we have 6 pencils in the stem, it just says she bought some pencils we do not know she bough 6 pencils until statement 1.
Oh, yes, sorry :D
In general ,to make the total price 130 cents we have only one combination


Anybody with 2nd question? :shock:
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by ajmoney09 » Wed Aug 20, 2008 5:50 pm
4meonly wrote:
ajmoney09 wrote:
4meonly wrote:About the 1st question:
From the table is can deduce that to make 130 cents we should by only 1 combination - 2*23 cents+4*21cents=130 cents.
Because from the main statement we know that we have nly 6 pencils.

Thats why (2) in SUFFicient making B the right answer

About 2nd question - no idea, too :(
But it does not say we have 6 pencils in the stem, it just says she bought some pencils we do not know she bough 6 pencils until statement 1.
Oh, yes, sorry :D
In general ,to make the total price 130 cents we have only one combination


Anybody with 2nd question? :shock:
For sure someone help with the second I was CONFUSED!

I am taking test on Friday....really nervous! :!:
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by parallel_chase » Wed Aug 20, 2008 6:28 pm
First of all dont be nervous. Its just one question, you have 37 different questions to face on quant.

from the question stem we can conclude:

500 is closer to x i.e. 400-600

400 is closer to y i.e. 300-500

Statement I

x < 500

x is closer to 400-499

we dont know anything about y. Insufficient.

Statement II

y < 400

y is closer to 300-399

we dont know anything about x. Insufficient.

Combining I & II
x is closer to 400-499
y is closer to 300-399


x+y = 400+300 = 700 x+y is closer to 700

or

x+y = 499+399 = 900 approx. is closer to 900

or that matter any values of x and y will give a range closer to either 700,800 or 900

Therefore Insufficient.

Hence E is the answer.

Let me know if you still have any doubts.

Good Luck!!!
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