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HardCover_Books

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by Suyog » Tue Aug 05, 2008 9:59 am
Using both (1) and (2):

If we say that, total cost of hardcover books that Juan bought $175 and the total cost of books is less than 260 then Juan can not buy more than 10 paperback books. So juan bought 6 Hardcover books.

Choose(c).
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by codesnooker » Thu Aug 07, 2008 1:37 am
Suyog wrote:Using both (1) and (2):

If we say that, total cost of hardcover books that Juan bought $175 and the total cost of books is less than 260 then Juan can not buy more than 10 paperback books. So juan bought 6 Hardcover books.

Choose(c).
Where does in the question it is written that Juan bought books of $175? :shock:

In the question it is clearly mention that hardcover books were bought for at least 150$ (So we can't ignore this case).

And suppose, if Hardcover books total price was $150. then amount left = 260 - 150 = 110.

Also it mentioned that total price was less then 260, so paperback books will be 109.99$ at max.

And in this, he can be either 10, 11, 12, or 13 paperback books.

So, in my opinion, answer (E) should be correct.

Let me know if I am doing mistake somewhere.
Thanks
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by Ian Stewart » Thu Aug 07, 2008 3:21 am
codesnooker wrote: And in this, he can be either 10, 11, 12, or 13 paperback books.
The question doesn't ask how many paperback books he bought. It asks how many hardcover books he bought. Suyog's solution is correct; if he spends $175 or more on hardcovers, the other conditions in the question can't be true. So he must have spent $150 on hardcovers - that is, he must have bought 6 hardcover books.
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Re: HardCover_Books

by olika » Thu Aug 07, 2008 2:47 pm
codesnooker wrote:Any Suggestion?
You can solve in this way

x is the number of paperback books
y is the number of hardcover books

we have:
the price of a paperback book is $8,
the price of a hardcover book - $25,
x>10

from the (1) we'll get: 25y greater or equal to 150
from the (2): 8x+25y<260

Solving (1), you'll get y greater or equal 6 -----> insuff.
As for (2), we have a set of equations: 8x+25y<260 and x>10. Solving this system, you'll get y<7.2 . So y should be less than 7 -----> insuff.

Statements taking together are suff.: 6<=y<7. So, y should be equal to 6.

The ans. C.
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by gmattester » Fri Aug 08, 2008 6:12 am
Ian Stewart wrote:
codesnooker wrote: And in this, he can be either 10, 11, 12, or 13 paperback books.
The question doesn't ask how many paperback books he bought. It asks how many hardcover books he bought. Suyog's solution is correct; if he spends $175 or more on hardcovers, the other conditions in the question can't be true. So he must have spent $150 on hardcovers - that is, he must have bought 6 hardcover books.
Can you plz. explain in details how you reached at this $175.
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Re: HardCover_Books

by santa_dem » Fri Aug 08, 2008 6:23 am
olika wrote:
codesnooker wrote:Any Suggestion?
You can solve in this way

x is the number of paperback books
y is the number of hardcover books

we have:
the price of a paperback book is $8,
the price of a hardcover book - $25,
x>10

from the (1) we'll get: 25y greater or equal to 150
from the (2): 8x+25y<260

Solving (1), you'll get y greater or equal 6 -----> insuff.
As for (2), we have a set of equations: 8x+25y<260 and x>10. Solving this system, you'll get y<7.2 . So y should be less than 7 -----> insuff.

Statements taking together are suff.: 6<=y<7. So, y should be equal to 6.

The ans. C.
Only one thing to object: solving the 8x+25y<260 and x>10 sistem will result in y<6.88, otherwise your explanation allows 2 solutions 6 and 7 (7<7.2).

Regards,
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by Ian Stewart » Fri Aug 08, 2008 12:23 pm
gmattester wrote:
Ian Stewart wrote:
codesnooker wrote: And in this, he can be either 10, 11, 12, or 13 paperback books.
The question doesn't ask how many paperback books he bought. It asks how many hardcover books he bought. Suyog's solution is correct; if he spends $175 or more on hardcovers, the other conditions in the question can't be true. So he must have spent $150 on hardcovers - that is, he must have bought 6 hardcover books.
Can you plz. explain in details how you reached at this $175.
Hardcovers cost $25 each. If he buys 7 or more hardcovers, he would spend at least 7*25 = $175. That isn't possible if you use the information from both statements, so he must have bought fewer than 7 hardcovers.
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by codesnooker » Mon Aug 11, 2008 6:53 am
What a silly mistake I did :shock: and even post on the forum also. :oops: Sorry for the trouble guys. I got it.
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