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saurabhmahajan
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Solution:
We have (x*1/100 + y*2/100 + z*3/100)/(x+y+z) = 1.5/100.
Or (x+2y+3z)/(x+y+z) = 1.5 = 3/2.
Or 2x+4y+6z = 3x+3y+3z.
Or x = y+3z.
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Rahul@gurome
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Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
