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by PAB2706 » Thu Oct 23, 2008 5:33 am
How many attendees are at a convention if 150 of the attendees are neither female nor students, one-sixth of the attendees are female students, two-thirds of the attendees are female, and one-third of the attendees are students?

300
450
600
800
900
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by stop@800 » Thu Oct 23, 2008 5:54 am
IMO E
Draw venn diagram, you will easily understand it.
Equation will be

T = 2T/3 + T/3 - T/6 + 150
solve ot you will get T = 900
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by cramya » Thu Oct 23, 2008 2:02 pm
Same approach

Total = Group1+Group2-both+neither

Let x be the toal number of attendees

x = x/3+2x/3-x/6+150
x-x/3-2x/3+x/6 = 150

x = 900
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by rohangupta83 » Thu Oct 23, 2008 3:16 pm
E? really? I got (B)

I didn't use a Venn diagram though. I'll post my solution shortly.
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by rohangupta83 » Thu Oct 23, 2008 3:23 pm
Let the total number of attendees = x

number of female attendees = 2x/3
number of male attendees = 1x/3 (which include male students + male non-students)............equation 1

number of students = 1x/3
number of female students = 1x/6
number of male students = 1x/6.............equation 2

number of male attendees not students = 150....equation 3

using equations 1, 2 and 3 we get:

1x/6 + 150 = 1x/3
150 = 1x/6
or x = 900

ahh my bad imo E - did a simple calculation error earlier.
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