Data Sufficiency

Of the students who eat in certain cafeteria, each student either like or dislikes lima beans and each student either like or dislikes Brussels sprouts. Of these students, 2/3 dislikes lima beans; and of those who dislike beans, 3/5 also dislikes Brussels sprouts. How many students like Brussels sprouts but dislikes lima beans?
1) 120 students eat in cafeteria
2) 40 of the student like lima beans

IMO (D)

Let's make a table

Lima| Brussel |
--------------------------------------
Like A | B |
Dislike C | D |

For the sake of convenience, Ive called these combos A,B,C,D.

Let there be x students in total

>2/3 dislikes lima beans (which also implies 1/3 like lima beans)
C = 2x/3 , A = x/3

>and of those who dislike beans, 3/5 also dislikes Brussels sprouts
D = 2x/5 , B = 3x/5

>How many students like Brussels sprouts but dislikes lima beans?
We need to find A + D = x/3 + 2x/5 = 11x/15

Both statement 1 and 2 give us the value of x, so each should be sufficient on its own.

Answer should Be D, ( even though the marked A First )

I missed the point that with II statement also we can get the answer.

thanks for posting such a brilliant question.