Given : x and y are integers
Q: Is x even
Stmt I
Rules:
even * odd = even
odd * even = even
x ( y+5) is even {even * odd = even or odd * even = even}
case 1:
x-> odd y+5 > even i.e y->odd
x->even y can be odd or even still x(y+5) will be even
INSUFF
Stmt II
Rules:
odd+odd = even
even + even = even
6y^2 + 41y + 25 - >even
6y^2 is always even since even * odd or even*even are both even so we cant say anyhting about y yet if its even or odd However 6y^2+41y combined has to be odd since only odd + 25(odd) - >even i.e 41y has to be odd and y has to be odd since 41 is odd and if y was even 41*y would be evn and not odd based on the rules above
All we know is y is odd x could still be even or odd
INSUFF
Stmt I and II together
y->odd y+5 is even so no matter what x (X COULD BE ODD OR EVEN) is x(y+5) will always be even based on rules in bold above
INSUFF
Choose
E)
P.S : I know there are lots of even's and odd's in the explanation so let me know if u still have questions...
Good luck!
Regards,
Cramya
