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If 1) is true, then m and p are both divisible by 2; in other words, m and p are both even. Whenever you divide one even number by another, the remainder must be even, so r cannot be 1. Since we're told r is not zero, then r must be greater than 1, and this statement is sufficient.sumatitandon wrote:The integers m and p are such that 2 < m< p , and m is not a factor of p, if r is the remainder , when p is divided by m , is r > 1?
1) The greatest common factor of m and p is 2
2) the least common factor of m and p is 30
. I think I miss understood your analysis of the second statement. I think I don't understand the difference between common factor and common multiple. Yes, that's exactly right.cramya wrote:
P.S: IMO when the question is " Is something greater than something" the equalt to case and lesser than case would fall in the NO bucket.
When a question reads " Is something lesser than something" then the equal to case and greater than case would fall in the NO bucket
Ian, please correct me if I am mistaken here.
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