Well, I'm not sure how you solved it, but here's what I did.
First, we have to solve for "a", so we have to plug in what we know: we know that the coffee was 120 degrees after 10 minutes, so:
120=120(2^-10a)+60
We can solve for a there and find that a=.1.
Now that we know "a", we can create a new equation to solve for the temperature after 30 minutes:
F=120(2^(30*.1))+60
Now we can solve for F, which would = 75.
Let me know if you want more details re: how to do the calculations - it's hard to type them out! I agree that this problem is pretty time consuming and I don't see much of a shortcut at first glance...
Major Timing Issue - Coffee (GMAT PREP) - need expert's help
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120=120(2^-10a)+60
60=120(2^-10a)
1/2=(2^-10a) so,
1/2=1/2^10a
How do u solve for "a" after this?
Since it is already mentioned in few posts that a= .1, after substituting the value for a the equation is:
F= 120(2^30*.1)+60
= 120(2^3)+60
.....solving got this equation gives a huge number....
where am i going wrong in solving for "a" n then in the substitution?
60=120(2^-10a)
1/2=(2^-10a) so,
1/2=1/2^10a
How do u solve for "a" after this?
Since it is already mentioned in few posts that a= .1, after substituting the value for a the equation is:
F= 120(2^30*.1)+60
= 120(2^3)+60
.....solving got this equation gives a huge number....
where am i going wrong in solving for "a" n then in the substitution?
hey... a= 1/10..... not 1.
here is the method , i think so you stuked at 1/2 = (1/2^a)^10,
cross multiplication..... 2^10a = 2 ^ 1
.....10a = 1
........a = 1/ 10 ....
Then substitute this a into that equation.....youw will be getting 15 + 60.
Hope thats clear
here is the method , i think so you stuked at 1/2 = (1/2^a)^10,
cross multiplication..... 2^10a = 2 ^ 1
.....10a = 1
........a = 1/ 10 ....
Then substitute this a into that equation.....youw will be getting 15 + 60.
Hope thats clear

















