Can someone explain this one - i thought the answer is C.
GMATPrep DS
This topic has expert replies
-
- Master | Next Rank: 500 Posts
- Posts: 136
- Joined: Sun Sep 28, 2008 8:20 pm
- Location: fssf
- Thanked: 17 times
From the Information given
(M-J)=2(M-K)
Therefore M=2k-J-----------(1)
Average of M, J, K = (M+J+K)/3-----(2)
From 1 and 2 the average reduces to K
therefore statement 2 is sufficient
OA B
(M-J)=2(M-K)
Therefore M=2k-J-----------(1)
Average of M, J, K = (M+J+K)/3-----(2)
From 1 and 2 the average reduces to K
therefore statement 2 is sufficient
OA B
Aiming High