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by jackcrystal » Fri Nov 07, 2008 6:34 pm
B ?
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by logitech » Fri Nov 07, 2008 6:48 pm
jackcrystal wrote:B ?
Yeap, B as in BANANA :o
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by cramya » Fri Nov 07, 2008 7:16 pm
Is it really B as in Banana; wow all this time I was thinking its B as in Boy.

Thanks Logitech ; :-) You are something!!!
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by EricLien9122 » Fri Nov 07, 2008 7:27 pm
What's the source of this question? I feel the question itself is sufficient unless I am missing something. If I pick 7 different #s and each is divisible by 7, the sum of remainder is 0?


Please correct me if I made a mistake.
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by logitech » Fri Nov 07, 2008 7:29 pm
EricLien9122 wrote:What's the source of this question? I feel the question itself is sufficient unless I am missing something. If I pick 7 different #s and each is divisible by 7, the sum of remainder is 0?


Please correct me if I made a mistake.
DIVIDED does not mean "divisible"

Oh the question is from GMAC. So we are cool! 8)
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by cramya » Fri Nov 07, 2008 7:37 pm
What's the source of this question? I feel the question itself is sufficient unless I am missing something. If I pick 7 different #s and each is divisible by 7, the sum of remainder is 0?


Please correct me if I made a mistake.
Hi Eric,
The sum of the reminders will be 0 only if u pick all the 7 numbers divisible by 7. In stmt I) we cannot do this since the range will be more than 6.

Stmt I is INSUFF

Eg: Lets say we pick numbers where the reminders are

1 2 3 4 5 7 7. The range is still 6 but the sum is 29

1 2 3 4 5 6 7 - The range is 6 but the sum is 28


Stmt II SUFF for 7 consecutive intgers the sum of the remainders will always be the same(21)

B)
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by EricLien9122 » Fri Nov 07, 2008 7:43 pm
ya, I think I need a new pair of glasses, I read "divisible" instead divide. Story of my life~

Thanks for correcting me btw.
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by Bidisha800 » Sat Nov 08, 2008 11:22 pm
The question said Seven DIFFERENT numbers are selected.

Doesn't that mean that the same number can not be repeated twice ?

All numbers will be distinct and their range will be 6. These two conditions give 7 consecutive integers in (A) as does (B).

I think answer should be (D).
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by cramya » Sat Nov 08, 2008 11:30 pm
I picked the wrong example. Your are right about 7 different numbers but still its B) and not D)

Lets say the numbers are

1 2 3 4 7 6 11

1 2 3 4 7 6 13

Range of the reminders is 6 in both sets but the sum different

Hope this helps!
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by teejayz » Sun Nov 09, 2008 7:45 am
Hi Cramya

Sorry I am confused by your last post.

1 2 3 4 7 6 11

1 2 3 4 7 6 13

Are they the remainders? The range will not be 6... also do you have any logic as to picking numbers, why skip 5...

thanks!
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by cramya » Sun Nov 09, 2008 7:56 am
Hi Cramya

Sorry I am confused by your last post.

1 2 3 4 7 6 11

1 2 3 4 7 6 13

Are they the remainders? The range will not be 6... also do you have any logic as to picking numbers, why skip 5...

thanks!
TJ,
These are the actual numbers picked not the remainders. I could have picked 5 instead of 6. I was trying to show for the 2 sets of numbers that the range of the remainders is 6 but the sums of remainders different. Hence stmt I INSUFF


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by teejayz » Sun Nov 09, 2008 8:11 am
ahh, gothya, thanks makes sense now :)
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by Bidisha800 » Sun Nov 09, 2008 2:51 pm
Hmmm ... I misread the statement in (A). I missed the fact that the range is for remainders and not for actual numbers.
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