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Wow, good answer. I got 1/2 after thinking it only applied to even numbers. Didn't think to have other options where the number has 8 in it.Tani Wolff - Kaplan wrote:your three integers are consecutive so there are two basic possibilities
if n is even, both n and n+2 are even. Also, one of them must be divisible by 4, so the product will be divisible by 8. That happens 48 times.
if n is odd, you have 2 odd numbers and one even number. For the product to be divisible by 8,the one even number (the middle one) must be divisible by 8. that will happen if n = 7,15,23,31,39,47,55,63,71,79,87 or 95 ( 12 times)
Total = (48+12)/96 = 60/96 = 5/8
Tani Wolff - Kaplan wrote:your three integers are consecutive so there are two basic possibilities
if n is even, both n and n+2 are even. Also, one of them must be divisible by 4, so the product will be divisible by 8. That happens 48 times.
if n is odd, you have 2 odd numbers and one even number. For the product to be divisible by 8,the one even number (the middle one) must be divisible by 8. that will happen if n = 7,15,23,31,39,47,55,63,71,79,87 or 95 ( 12 times)
Total = (48+12)/96 = 60/96 = 5/8
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