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if 0<x<1,what is the median of the values x,x^-1,x^2,s

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by ajith » Tue Feb 02, 2010 9:12 am
bhumika.k.shah wrote:if 0<x<1,what is the median of the values x,x^-1,x^2,sq rt x and x^3

A.x
B.x^-1
C.x^2
D.sq rt x
E.x^3
to find the median one has to arrange the numbers in ascending or descending order and choose the middle one

x^3 will be the least, followed by
x^2 , then by
x
sqrt(x), and
x^-1

so x is the median

A
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by bhumika.k.shah » Tue Feb 02, 2010 9:13 am
i wish it was so easy for me too :-(
ajith wrote:
bhumika.k.shah wrote:if 0<x<1,what is the median of the values x,x^-1,x^2,sq rt x and x^3

A.x
B.x^-1
C.x^2
D.sq rt x
E.x^3
to find the median one has to arrange the numbers in ascending or descending order and choose the middle one

x^3 will be the least, followed by
x^2 , then by
x
sqrt(x), and
x^-1

so x is the median

A
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by thephoenix » Tue Feb 02, 2010 9:24 am
bhumika.k.shah wrote:if 0<x<1,what is the median of the values x,x^-1,x^2,sq rt x and x^3

A.x
B.x^-1
C.x^2
D.sq rt x
E.x^3
since 0<x<1
x is a fractional no.
property of fractional no is that for a f/r no raised to some power the higher the value of power the lower is the no. and so is the converse
so
x^3<x^2<x<x^0.5<x^-1
hence x is the median
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by bhumika.k.shah » Tue Feb 02, 2010 9:28 am
thephoenix wrote: since 0<x<1
x is a fractional no.
property of fractional no is that for a f/r no raised to some power the higher the value of power the lower is the no. and so is the converse
so
x^3<x^2<x<x^0.5<x^-1
This is what i needed to learn. thanks!
:-)
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