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GMATBootcamp Starts Sep 21
Chris Peckover, Target Test Prep GMAT expert
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Live Online Bootcamp Class with Top GMAT Expert Chris Peckover

Sep 21 to Oct 9, 2026

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Mon to Fri · 7:00 to 10:00 PM ET
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Sep 6 to Dec 6, 2026

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GMAT PREP QUESTION

Expert replies
Source: — Problem Solving |

by vishubn » Sun Oct 05, 2008 5:31 pm
Hi sparsh!

this is how i did it !

total number of students =30

2 never buy ! so effectively we r talking abt 28 students

12(1)= 12 books
10 buy 2 books each = 20 books
remaining 6 should buy 3 miminum

but ! one student can have maximum !

but number of books avalaible is avg=2/student
=60 books in total

12+20=32 books and remaining 28 books for 6 students

now ! 5 will get their minimum share and 1 will get the max( thats the whole point )

5(3)+1(x)=28

x=13 books

Vishu

p.s.- this question has been answered in previous post
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by artistocrat » Mon Oct 06, 2008 10:00 pm
Average=Sum/Number

2=[(2)(0)+(12)(1)+(10)(2)+(5)(3)+x]/30;x=13
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by stop@800 » Mon Oct 06, 2008 11:17 pm
I can not see the image :(
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