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Source: — Problem Solving |
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by sujaysolanki » Tue Dec 25, 2007 5:02 am
Picking numbers is best here

say x =15
2^15 - 2^13 = 2^13(4-1) = 2^13(3)

Hence D
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by preciousrain7 » Thu Dec 27, 2007 2:09 pm
sujaysolanki wrote:Picking numbers is best here

say x =15
2^15 - 2^13 = 2^13(4-1) = 2^13(3)

Hence D
Hi, I'd really appreciate it if you can explain how you get 2^13(4-1)

Thanks a lot

Sonia
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by cris » Thu Dec 27, 2007 3:13 pm
[(2^x)]-[(2^x)/(2^2)] = (2^x) (3/4)

and we know:

(2^x)(3/4)= (2^13) (3)

x must be 15

I think this way is faster
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by cris » Thu Dec 27, 2007 3:15 pm
[(2^x)]-[(2^x)/(2^2)] = (2^x) (3/4)

and we know:

(2^x)(3/4)= (2^13) (3)

x must be 15

I think this way is faster
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by preciousrain7 » Thu Dec 27, 2007 3:25 pm
cris wrote:[(2^x)]-[(2^x)/(2^2)] = (2^x) (3/4)

and we know:

(2^x)(3/4)= (2^13) (3)

x must be 15

I think this way is faster
THANK YOU SO MUCH!!!!! I FINALLY GET IT!
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