Picking numbers is best here
say x =15
2^15 - 2^13 = 2^13(4-1) = 2^13(3)
Hence D
BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course
Redeem
Featured Course
Target Test Prep GMAT OnDemand
Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.
- 715+ score guarantee — highest in the industry (99th percentile)
- 52 chapters · 1,500+ lessons · 4,000+ practice questions
- 400 hours of video · 1,500+ instructor-led HD smartboard lessons
- 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
- 24/7 live support + weekly Zoom office hours with GMAT instructors
- TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
- 1,200+ flashcards + AI-powered study assistant & daily calendar
- OnDemand, LiveTeach & GMAT Bootcamp formats available
- Also: GRE, SAT Math & Executive Assessment courses
- MBA Admissions Consulting now available
- 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
- 200,000+ students served
- 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★
5.0
(559 reviews)
130-pt guarantee
$0 to start
then $127/mo
GMAT Prep
Source: Beat The GMAT — Problem Solving |
Hi, I'd really appreciate it if you can explain how you get 2^13(4-1)sujaysolanki wrote:Picking numbers is best here
say x =15
2^15 - 2^13 = 2^13(4-1) = 2^13(3)
Hence D
Thanks a lot
Sonia
[(2^x)]-[(2^x)/(2^2)] = (2^x) (3/4)
and we know:
(2^x)(3/4)= (2^13) (3)
x must be 15
I think this way is faster
and we know:
(2^x)(3/4)= (2^13) (3)
x must be 15
I think this way is faster
[(2^x)]-[(2^x)/(2^2)] = (2^x) (3/4)
and we know:
(2^x)(3/4)= (2^13) (3)
x must be 15
I think this way is faster
and we know:
(2^x)(3/4)= (2^13) (3)
x must be 15
I think this way is faster
THANK YOU SO MUCH!!!!! I FINALLY GET IT!cris wrote:[(2^x)]-[(2^x)/(2^2)] = (2^x) (3/4)
and we know:
(2^x)(3/4)= (2^13) (3)
x must be 15
I think this way is faster
