This can be easily solved by picking numbers.
Choosing integers will give a relation that is not mentioned in the choices.
So choose a fraction. say 0.2


I. x^2 < 2x < 1/x
II. x^2 < 1/x < 2x
III. 2x < x^2 < 1/x

x = 0.2

x^2 = 0.04
2x = 0.4
1/x = 1/0.2 = 10/2 = 5

x^2 < 2x < 1/x

ie. Stmt I

HT helps

Actually both I and II are true. To show this, you can use 0.99 for statement II and it will hold true.

OA should be D. Stmt 2 is correct as well. Take 0.9 as an example..no easy method that i could think of, just trial and error knowing that you should move from 0 to 1

Why did you not substitute any natural(non decimal) nos. ?How did you guess that the number to be substituted was decimal?

You want to try different combinations of positive numbers. With positive numbers, you'll generally want to try a fraction (decimal) and a non-fraction. Since we see squares, fractions and multiples of numbers, you'll want to use fractions and non-fractions when testing because they act differently in these situations.

For instance:

1/x > x^2

If x is 1/2, then the inequality is true
If x is 2, it is false.