BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

gmat prep

Expert replies
Source: — Problem Solving |

by jeenashiva » Fri Sep 19, 2008 6:58 am
Yes, the answer is C. We need both statements to find the answer.


Statement 1:

it indicates both the Max number and Min number can be negative or Positive.

Negative * negative = positive
Positive * positive = positive

But it does not say how many number are there.

Statement 2:
It says that there are even numbers in the set.

If you multiply any even number of positive numbers, the answer will be always positive.

Also, if you multiply any even number of negative numbers, the answer will be always positive.

(-1 * -4* -5* -6 = +120)

So we need both statements to find the answer.
Join the discussion

by bbaah » Fri Sep 19, 2008 7:15 am
(1) If the product is of the greatest and smallest integers is+ve, then the integers are either both positive or both negative.

Eg. 1x7 =7, (+), -1x-7 = 7, also (+),

However, without further information about the number of integers in the list, one cannot tell the sign of the product. Not Sufficient.

(2) If there is an even number of integers in the list, the product can be either positive or negative.

Eg. 1x7 = 7 (+)
-1x7 = -7 (-)

Not Sufficient.

Considering both statements,

If there is an even number of integers in the list, and the product of the greatest and smallest integers in the list is positive, then the product of all the integers must also be positive, since the product of an even number of +ve integers is +ve, and the product of an even number of -ve integers will also be +ve.

Eg. (+)(+)(+)(+) = (+)

(-)(-)(-)(-) = (+)

Also, remember from the explanation in (1) above that since the product of the greatest and smallest integers is positive, the numbers must all be either positive or negative. You can't have (-1)(1)(2)(7) as the product because (-1)(7) = -7, which violates the requirement that the product of the greatest and smallest integers be +ve.

Both statements together are sufficient to answer the question in the stem, but neither statement alone is sufficient.
Join the discussion

by cramya » Fri Sep 19, 2008 2:24 pm
Take stmt 1)

If the product of greatest and smallest is positive then both these numbers either are positive or negative.

If they are negative then there is no telling if the product of all in the list is postive

Stmt 1)by itself is insufficient so it bolis down to B,C,E

Take stmt 2

There is a even set of elements in the list

stmt 2 by itself doesnt gaurantee the product of all elements to be positive
since the elemenst could all be positive all be negative or a combinaion of pos and neg

When we take stmt1 and stmt2 together we know the highest and lowest are both neg or both pos and if it all negative then the product of even number of negative numbers is always positive. If its all positive the the product is always positive

there fore C)
Join the discussion

by vaivish » Fri Sep 19, 2008 11:13 pm
thanks for the replies. But i think we are assuming here that we have either all the integers as + or -, which is not a valid assumptions.

e.g. If we have -3,-1, 2, -5...in this case the 1st and 2nd statements get satisfied. But still we cant say that the product is +.

The argument only says list of different integers. It can be mixed one as i have mentioned above. But while answering all of you have assumed that all integers are either + or -.


Any thoughts on this?
Join the discussion